No.  Operation        Receiving          Statement of results
 1   ¹V₂ × ¹V₃        ¹V₄, ¹V₅, ¹V₆      = 2n
 2   ¹V₄ − ¹V₁        ²V₄                = 2n − 1
 3   ¹V₅ + ¹V₁        ²V₅                = 2n + 1
 4   ²V₅ ÷ ²V₄        ¹V₁₁               (the operands are reversed; the note intends (2n−1)/(2n+1))